3.3t^2+8.7t=9.4t^2

Solution for 3.3t^2+8.7t=9.4t^2 equation:

3.3t^2+8.7t=9.4t^2

We move all terms to the left:

3.3t^2+8.7t-(9.4t^2)=0

We get rid of parentheses

3.3t^2-9.4t^2+8.7t=0

We add all the numbers together, and all the variables

-6.1t^2+8.7t=0

a = -6.1; b = 8.7; c = 0;
Δ = b2-4ac
Δ = 8.72-4·(-6.1)·0
Δ = 75.69
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8.7)-\sqrt{75.69}}{2*-6.1}=\frac{-8.7-\sqrt{75.69}}{-12.2}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8.7)+\sqrt{75.69}}{2*-6.1}=\frac{-8.7+\sqrt{75.69}}{-12.2}
$